(D) The atomic number of Palladium $(Pd)$ is $46$. The electronic configuration of $Pd$ in its ground state is $[Kr] 4d^{10} 5s^0$. The value $l = 2$

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(D) The atomic number of Palladium $(Pd)$ is $46$. The electronic configuration of $Pd$ in its ground state is $[Kr] 4d^{10} 5s^0$. The value $l = 2$ corresponds to the $d$-subshell. In the $4d^{10}$ configuration,there are $10$ electrons in the $d$-subshell. Therefore,the number of electrons with $l = 2$ is $10$.